# Routine for Multi-Stress Weibull Plotting Example # Coded by Reuel Smith 2015-2017 # ======================================================================== # Example Problem 4.7 # Consider an accelerated test where temperature is the accelerating # variable and 20 units were tested to failure assuming complete failures # (no censoring). Eight units were tested at 406 K, and six units each at # 436 K and 466 K, with times to failure tabulated below. Assuming an # Arrhenius-Weibull life-stress relationship, find the parameters of the # model, using both the plotting method and MLE method and compare the # results. Find the expected life at the use level temperature of 353 K # and compare the results. # # Temperature Time to Failure (hrs) # =========== ===================================== # 406 K 248 456 528 731 813 965 972 1528 # 436 K 164 176 289 319 386 459 # 466 K 92 105 155 184 219 235 # # Solution: # This routine will only cover the Weibull multi-plot at the three # different stress levels. # ======================================================================== # PART 1: Initialize data and constants # ======================================================================== # sorting the times to failure in ascending order # CHANGE these values to process your own data TTF1 <- sort(c(248,456,528,731,813,965,972,1528)) TTF2 <- sort(c(164,176,289,319,386,459)) TTF3 <- sort(c(92,105,155,184,219,235)) # set the length of the TTF vector or the number of failures n1 <- length(TTF1) n2 <- length(TTF2) n3 <- length(TTF3) # CDF or unreliability for probability plot at Stress Levels 1, 2, and 3 i1 <- c(1:n1) # uncensored data points from 1 to n1 i2 <- c(1:n2) # uncensored data points from 1 to n2 i3 <- c(1:n3) # uncensored data points from 1 to n3 # Median plotting position (i - 0.3)/(n + 0.4). Other plotting positions # may be assumed: # KIMBALL - (i - 0.375)/(n + 0.25) # MIDPOINT - (i - 0.5)/n # MEAN - i/(n + 1) F1 <- 100*((i1-0.3)/(n1+0.4)); F2 <- 100*((i2-0.3)/(n2+0.4)); F3 <- 100*((i3-0.3)/(n3+0.4)); # Weibull scale conversion of the Failure Percent data F1B <- log(log(1/(1-F1/100))) F2B <- log(log(1/(1-F2/100))) F3B <- log(log(1/(1-F3/100))) # reliability for probability plot R1 <- (100-F1)/100 R2 <- (100-F2)/100 R3 <- (100-F3)/100 # Form a matrix to categorize the results of the above analysis. # Column 1 displays the TTFs, Column 2 displays the calculated Failure # Probability, and Column 3 displays the Reliability #TTFtable <- matrix(c(1:(3*n)), nrow = n, ncol = 3, byrow = TRUE,dimnames = list(c("1", "2", "3", "4", "5"),c("TTF", "Failure Probaility (%)", "Reliability (%)"))) #TTFtable[,1] <- TTF #TTFtable[,2] <- F #TTFtable[,3] <- R*100 # Scale conversion to Weibull plot scale # Upper and lower bounds of the Percent Failure axis in percent fc <- c(.1,99.9) # Weibull scale conversion of the upper and lower bounds of the Percent # Failure axis fcB <- log(log(1/(1-fc/100))); # Percent Failure ticks cited between the lower and upper bounds Pticks1 <- c(0.1,0.2,0.3,0.4,0.5,0.6,0.7,0.8,0.9,c(1:10),10*c(2:9),95,99,99.9) # Weibull scale conversion of Percent Failure ticks cited between the lower # and upper bounds Pticks <- log(log(1/(1-Pticks1/100))) # Percent Failure labels for the y-axis Pticks1label <- c(0.1,0.2,0.3,"",0.5,"","","","",1,2,3,"",5,"","","","",10*c(1:9),95,99,99.9) # ======================================================================== # PART 2: Solve for Weibull Parameters alpha and beta # ======================================================================== # The Weibull parameters alpha and beta may be computed by assuming a # relationship for the reliability function R(t) = exp[-(t/alpha)^beta] or # 1/R(t) = exp[(t/alpha)^beta]. The relation translates to: # # ln[ln(1/R(t))] = beta*ln(t) - beta*ln(alpha) # # The LM function is used to fit this linear relationship and extract # the Weibull parameters alpha and beta. See Reliability Engineering and # Risk Analysis: A Practical Guide Section 3.3.2.2. for method. yfit1 <- log(log(1/R1)) yfit2 <- log(log(1/R2)) yfit3 <- log(log(1/R3)) xfit1 <- log(TTF1) xfit2 <- log(TTF2) xfit3 <- log(TTF3) # Calculates the slope beta and the intercept beta*ln(alpha) needed to # extract the Weibull parameters wblparm1 <- lm(yfit1 ~ poly(xfit1, 1, raw=TRUE)) wblparm2 <- lm(yfit2 ~ poly(xfit2, 1, raw=TRUE)) wblparm3 <- lm(yfit3 ~ poly(xfit3, 1, raw=TRUE)) beta1 <- summary(wblparm1)$coefficients[2,1] beta2 <- summary(wblparm2)$coefficients[2,1] beta3 <- summary(wblparm3)$coefficients[2,1] alpha1 = exp(-summary(wblparm1)$coefficients[1,1]/beta1) alpha2 = exp(-summary(wblparm2)$coefficients[1,1]/beta2) alpha3 = exp(-summary(wblparm3)$coefficients[1,1]/beta3) # CHANGE NROW if you have a different number of TTF data sets wblresults <- matrix(c(alpha1,beta1,alpha2,beta2,alpha3,beta3), nrow = 3, ncol = 2, byrow = TRUE,dimnames = list(c("Wbl Parameters 1","Wbl Parameters 2","Wbl Parameters 3"),c("alpha", "beta"))) betamean <- mean(wblresults[,2]) # ======================================================================== # PART 3: Weibull probability plot # ======================================================================== # Plot points at 0.1% and 99.9% # These have a different polynomial pair than that which was used to find # the alpha and beta intercept1 <- summary(wblparm1)$coefficients[1,1] intercept2 <- summary(wblparm2)$coefficients[1,1] intercept3 <- summary(wblparm3)$coefficients[1,1] ttfc1 <- c(exp((log(log(1./(1-0.001)))-intercept1)/beta1),exp((log(log(1./(1-0.999)))-intercept1)/beta1)) ttfc2 <- c(exp((log(log(1./(1-0.001)))-intercept2)/beta2),exp((log(log(1./(1-0.999)))-intercept2)/beta2)) ttfc3 <- c(exp((log(log(1./(1-0.001)))-intercept3)/beta3),exp((log(log(1./(1-0.999)))-intercept3)/beta3)) totttfc <- c(ttfc1,ttfc2,ttfc3) # Computes the upper and lower bound for the TTF axis in terms of log-time signs1 <- c(floor(log10(min(totttfc))):ceiling(log10(max(totttfc)))) logtimes1 <- 10^signs1 logspace <- c("","","","","","","","") Pticks1X <- c(1:(9*length(logtimes1)-8)) Pticks1X[1] <- logtimes1[1] Pticks1Xlabel <- Pticks1X # Calculates the tick values used for the final plot for(i2 in 1:(length(signs1)-1)){ Pticks1X[(9*i2-7):(9*(i2+1)-8)] <- logtimes1[i2]*c(2:10) Pticks1Xlabel[(9*i2-7):(9*(i2+1)-8)] <- c("","","","","","","","",logtimes1[i2+1]) } # The probability plot # DEFAULT XLAB HEADING is in "Time (hours)". When using a different unit of # time or measurement, CHANGE XLAB HEADING BELOW. Also ADD or SUBTRACT stress # levels as needed according to the setup # STRESS LEVEL 1 PLOT plot(TTF1, F1B, log="x",col="blue", xlab="Time (hours)", ylab="Percent Failure", pch=16, xlim=c(min(logtimes1), max(logtimes1)), ylim=c(min(fcB), max(fcB)), axes=FALSE) lines(ttfc1, fcB, col="blue") # STRESS LEVEL 2 PLOT points(TTF2, F2B, col="red", pch=17) lines(ttfc2, fcB, col="red") # STRESS LEVEL 3 PLOT points(TTF3, F3B, col="green", pch=18) lines(ttfc3, fcB, col="green") axis(1, at=Pticks1X,labels=Pticks1Xlabel, las=2, cex.axis=0.7) axis(2, at=Pticks,labels=Pticks1label, las=2, cex.axis=0.7) #Add horizontal grid abline(h = Pticks, lty = 2, col = "grey") #Add vertical grid abline(v = Pticks1X, lty = 2, col = "grey") # The legend heading # The first two places signify where the legend will be located. CHANGE the # legend labels in the LEGEND="" portion. PCH changes the label # types and LTY changes the line types. legend(10^signs1[1], log(log(1/(1-.99))), legend=c("Stress Level 1 - 406 deg K", "Stress Level 2 - 436 deg K", "Stress Level 3 - 466 deg K"), col=c("blue", "red", "green"), pch=c(16,17,18), cex=0.8, text.font=4, bg='white') wblresults
Top